Alexander (@tehada) started discussion #97
The processor starts working in real mode. Let's back up a little and try to understand memory segmentation in this mode. Real mode is supported on all x86-compatible processors, from the 8086 all the way to the modern Intel 64-bit CPUs. The 8086 processor has a 20-bit address bus, which means that it could work with a 0-0xFFFFF address space (1 megabyte). But it only has 16-bit registers, which have a maximum address of 2^16 - 1 or 0xffff (64 kilobytes). Memory segmentation is used to make use of all the address space available. All memory is divided into small, fixed-size segments of 65536 bytes (64 KB). Since we cannot address memory above 64 KB with 16 bit registers, an alternate method is devised. An address consists of two parts: a segment selector, which has a base address, and an offset from this base address. In real mode, the associated base address of a segment selector is Segment Selector * 16. Thus, to get a physical address in memory, we need to multiply the segment selector part by 16 and add the offset:
On the fourth line typo.